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I am trying to find the answer to this integral problem

9 dx
-------
xln3x

I had a previous question that was the same but the answers were incorrect...
I'm completely lost when it comes to integrating fractions, could someone give me a boost?

2007-11-28 15:12:40 · 2 answers · asked by ret80soft 1 in Science & Mathematics Mathematics

2 answers

∫9 / xln3x dx
= ∫9/ln3x dln3x, mental substitution
= 9ln|ln3x| + c
-------
Ideas to save time: Use mental substitution.

2007-11-28 15:20:20 · answer #1 · answered by sahsjing 7 · 1 0

Use substitution. Let u = ln(3x). Then du = (1/x) dx and you get

∫ 9du/u

which you should have no trouble integrating.

2007-11-28 15:22:15 · answer #2 · answered by Ron W 7 · 0 0

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