x^4-13x^2+36=0
i got x^2- 6.5x=-36
then i needed to square the 6.5 but I don't have a calculator..
Formula -(b)+-RARICAL (B^2-4ac)/(2A)
3x^2-6x=24
a.3
b.6
c.-24
I got 22 and 12
write 4 and -1 in quadratic formula
I got (x-4) (x--1)
2007-11-28 15:08:44 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
x^4-13x^2+-36=0 hence ( x^2-9)(x^2-4)=0
(x-3)(x+3)(x+2)(x-2)=0 hence
x1=3 x2=-3 x3=-2 x4=2
2007-11-28 15:17:22 · answer #1 · answered by Faisal R 3 · 0⤊ 0⤋
Which question do you want answered anyway?
For the first one, you keep everything on one side of the equation until you have "completed the square", so you would have......
x^4 - 13x^2 + (6.5)^2 -( 42.25-36) = 0
then..... [ x^2 - 6.5 ]^2 = 6.25 and
[ x^2 - 6.5 ] = +/- 2.5 from which x= +/-2 or +/-3.
2007-11-28 15:22:15 · answer #2 · answered by cattbarf 7 · 0⤊ 0⤋