check your answers. Put those numbers where the X and see if both side equal the same. If they don't then you have the wrong answers.
2007-11-28 15:08:04
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answer #1
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answered by Shanna Saunders 1
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The only mistake you made was not to first put it into standard form. You have to have 0 on the right-hand side. It becomes:
3x^x - 2x - 10 = 0
The discriminant becomes b^2 - 4ac = 4 + 4.3.10 = 124
( 2 +/- root(124) ) / 6
= 2.189 or -1.523
Check by substitution - these are correct.
2007-11-28 23:11:26
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answer #2
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answered by Anonymous
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a x^2 + b x + c = 0
x = [ -b +/- SQRT( b^2 - 4ac ) ] / 2a
In your problem
a = 3
b = -2
c = -10
b^2 - 4ac = 4 - 4(3)(-10) = 4 +120 = 124
SQRT(124) = 2*SQRT(31) = 11.136 (approximately)
x = [2 +/- 2â31 ] / 6
I don't get 0.6 nor 0.83
2007-11-28 23:15:48
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answer #3
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answered by Raymond 7
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so the quadratic formula reads x= -b +/- squareroot of b^2 - 4ac all over 2a
so the answers to your problem are [1/3(1+/- squareroot of 31)]
so the answers written out in words because it may be a little unclear, are, one third times one plus or minus the square root of 31.
if you have further questions you can email me, if you have a graphing calculator, its very easy to come up these answers, you just graph the function, and the line y = 0, and find the two intersection points. glad to help
2007-11-28 23:18:28
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answer #4
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answered by P 3
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no bc first you have to set the equation to 0
so you get 3x^2-2x-10=0
then plug them in
2+-2^2-4 3 -10 /2 3
2 +- 4+120 /6
2 +- Sr 124 /6
(2+11.14)/6 (2-11.14)/6
2.19 -1.523
2007-11-28 23:09:32
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answer #5
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answered by Briana L 4
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you have to set the equation to the quadratic form (ax^2+bx+c=0) first, that is 3x^2 - 2x - 10 = 0. to find for x or the root of the equation, just use the quadratic formula n this website:
http://en.wikipedia.org/wiki/Quadratic_formula#Quadratic_formula
a=3, b=negative 2 and c= negative 10
your answers would be negative 1.52258812 or simply negative 1.52 and 2.1892547 or 2.19 only.
=]
2007-11-28 23:28:46
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answer #6
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answered by dr.psycho 2
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3x^2 - 2x = 10 --> 3x^2 - 2x - 10 = 0
D = sqrt(b^2 - 4ac) = sqrt(4 - 4*3*(-10)) = sqrt(4 + 120)
D = sqrt(124) = 2 sqrt(31)
x1 = (-b + D)/2a = (2 + 2 sqrt(31)) / 6 = 2(1 + sqrt(31)) / 6
--> = (1 + sqrt(31)) / 3 = 2.18925478761
x2 = (-b - D)/2a = (2 - 2 sqrt(31)) / 6 = 2(1 - sqrt(31)) / 6
--> = (1 - sqrt(31)) / 3 = -1.52258812
2007-11-28 23:19:49
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answer #7
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answered by Seto 2
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did you reright the forumula in ax^2+bx+c?
3x^2 - 2x - 10 = 0
a = 3
b= -2
c = -10
so it wouldnt be - 4 (3) (10), it would be - 4 (3) (-10), which makes it +120
=/
2007-11-28 23:11:10
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answer #8
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answered by Gucci G 2
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x= -b +/- sqrt (b^2-4ac)/2a
a=3, b=-2,c=0
x=2+/- sqrt (4)/2(3)
x=2/3, 0
2007-11-28 23:08:47
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answer #9
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answered by Anonymous
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seems ok
2007-11-28 23:06:07
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answer #10
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answered by Juan O 6
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