{4x+8y=8000 2x+y=1300? what is the intersection point and how do you get it?

Answer 1

2X +y = 1300
y = 1300 - 2x
substitue in eq 1
4X + 8(1300 -2X) = 8000
devide by 4
X + 2(1300 - 2x) = 2000
X + 2600 - 4X = 2000
3X = 600
X = 200
y = 1300 - 2 *200 = 900

(X, Y) = (200, 900)

Answer 2

Solve the system, if possible, by substitution or elimination.
4x+8y=8000
x + 2y = 2000
x = 2000 - 2y (i)

2x + y = 1300 (ii)
Substitute (i) into (ii):
2(2000 - 2y) + y = 1300
4000 - 4y + y = 1300
-3y = 1300 - 4000
-3y = -2700
y = 900

x = 2000 - 2(900) = 200
The lines intersect at the point (200, 900).

ck. 2(200) + 900 = 400 + 900 = 1300.

Answer 3

Use elimination. Multiply 2x+y=1300 by -2 to get -4x-2y=-2600. Then add that plus 4x+8y=8000, to get 6y=5400, y=900. Plugin y as 900 in to either of the original equations, such as, 2x+900=1300. 2x=400, x=200.

Answer 4

Solve for x and y. The point you get will be the intersection.

2x+y=1300
y=1300-2x

Substitute in the other equation
4x+8 (1300-2x) =8000
4x +1040-16x=8000
-12x +10400=8000
-12x = -2400
x=200

y=1300-2x
y=1300-2(200)
y=1300-400
y=900

The point of intersection is (200,900)

Answer 5

4x + 8y = 8000
i.e. x + 2y = 2000
i.e. x = 2000 - 2y

substitute x into second equation

2(2000 - 2y) + y = 1300
i.e. 4000 - 4y + y = 1300
i.e. 4000 - 3y = 1300
i.e. 3y + 1300 = 4000
i.e. 3y = 2700
i.e. y = 900

so, to find x, x = 2000 - 2 x 900

x = 200

so the intersect is (x,y) i.e. (200,900)

Answer 6

for this problem i would use substitution
4x+8y=8000
y=1300-2x
then you would substitute the 2nd equation in where the y is in the first equation so it would read 4x+8*(1300-2x)=8000
combine like terms and solve it for x
then when you solve that equation substitute that answer in one of the equations in order to get the y value
x=200
y=900
(200,900)

Answer 7

the first eq can be rewirtten as x+2y=2000
from the second equation y=1300-2x

then substitute it into the first equation x+2*(1300-2x)=2000
Solve it for x, and then get y

Answer 8

use the elimination method in solving systems of linear equations. you only have to make the coefficients of the variable to be eliminated numerically equal and then add or subtract to eliminate that variable. then solve for the value of the remaining variable. substitute that value to one of the original equations to obtain the value of the other variable.

4x+8y=8000
2x+ y=1300

decide which variable (x or y) you want to eliminate. x is easier to eliminate because you only have to multiply the 2nd equation by 2 to make it 4x. the system now becomes:

4x+8y=8000
4x+2y=2600

subtracting will eliminate x and we have:

6y = 5400
y=900 (divide both sides by 6)

substitute y=900 to one of the original equations. using the 2nd equation:

2x+y=1300
2x+900=1300
2x=400 (subtract 900 from both sides)
x = 200 (divide both sides by 2)

so the point of intersection is given by the ordered pair (200,900).

Answer 9

4x + 8y =8000 reduced is x + 2y= 2000
2x + y= 1300
x+2y= 2000
x - y = 700
x= y + 700
4 (y + 700) + 8y= 8000
4y + 2800 + 8y= 8000
12y + 2800= 8000
12y= 5200
y= 433.3
2x+ 433.3= 1300
2x = 866.7
x = 433.35
(433.35, 433.3)

Answer 10

2x+y=1300
y=1300-2x
---------------
4x+8y=8000
x=2000-2y we have y=1300-2x
x=2000-2(1300-2x)
x=200

then submittening x value in 2x+y=1300

y=900


i think ;this will help you..........