y intercept means x=0
y=-(0-4)^2-25
y=-16-25
y=-9
2007-11-28 13:17:26
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answer #1
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answered by someone2841 3
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y= -(x-4)² - 25
= -(x² - 8x + 16) - 25
= -x² + 8x - 41
The y-intercept is the value of the function for x=0:
y-incp = -0² + 8â0 - 41 = -41
2007-11-28 21:23:53
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answer #2
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answered by DWRead 7
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no, the y- intercept is
you set x=0. then -4 times -4= 16 but then you account for the negative in front of the parentheses, so it is -16 then minus another 25
u get -41
2007-11-28 21:27:47
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answer #3
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answered by Anonymous
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-41. To find the y-intercept, set x=0 and solve for y
2007-11-28 21:17:00
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answer #4
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answered by Samson the Guinea Pig 3
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y-intercept:
(0, __)
y = -(0-4)^2 - 25
y = -(-4)^2 - 25
y = -(16) - 25
y = 9
y-intercept: (0,9)
2007-11-28 21:17:32
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answer #5
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answered by sayamiam 6
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-9
2007-11-28 21:18:35
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answer #6
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answered by Texfiєldяvox▒≠ღ♫♠♥♦♣©™ 3
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is there anyother homework problems we can do for you?
2007-11-28 21:21:01
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answer #7
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answered by jordan p 2
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