2007-11-28 11:53:57 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
u^4 + u²v² + v^4
= u^4 + 2u²v² + v^4 - u²v²
= (u² + v²)² - (uv)²
= (u² + uv + v²)(u² - uv + v²)
2007-11-28 11:57:56 · answer #1 · answered by gudspeling 7 · 3⤊ 1⤋
u^4 + u^2v^2 + v^4
= (u^2 + v^2)^2 -- (uv)^2
= (u^2 + uv + v^2)(u^2 -- uv + v^2)
2007-11-28 19:58:44 · answer #2 · answered by sv 7 · 1⤊ 1⤋
u^4 + u²v² + v^4
= u^4 + 2u²v² + v^4 - u²v²
= (u² + v²)² - (uv)²
= (u² + uv + v²)(u² - uv + v²)
this is the right answer!!
2007-11-28 19:59:05 · answer #3 · answered by Anonymous · 3⤊ 2⤋
u^4 + u^2v^2 + v^4 =
u^4 + 2u^2v^2 + v^4 - u^2v^2 =
(u^2 + v^2)^2 - (uv)^2 =
(u^2 + uv + v^2)(u^2 - uv + v^2) =
(u^2 + 2uv + v^2 - uv)(u^2 - 2uv + v^2 + uv) =
((u + v)^2 - uv)((u - v)^2 + uv) =
(u + v + âuv)(u + v - âuv)(u + v + iâuv)(u + v - iâuv)
2007-11-28 20:14:27 · answer #4 · answered by Helmut 7 · 0⤊ 5⤋
(u^2 + uv + v^2)(u^2 - uv + v^2)
2007-11-28 19:59:42 · answer #5 · answered by Anonymous · 1⤊ 2⤋
(u^2+v^2)(u^2+v^2)
2007-11-28 19:58:12 · answer #6 · answered by Ms. Exxclusive 5 · 1⤊ 5⤋
u^2(u^2 + v^2) + v^4 or, alternatively,
v^2(u^2 + v^2) + u^4 . both are equivalent.
2007-11-28 19:59:57 · answer #7 · answered by Mike 2 · 0⤊ 5⤋