a man pulls a sled at a constant velocity across a horizontal snow surface. if a force of 60N is being applied to the sled rope at an angle of 53 degrees to the ground, what's the force of friction between the sled and snow?
2007-11-28 11:53:55 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Physics
What's the mass of the sled? Since it wasn't given the answer will contain the constant m where you need to plug in the mass in kg
Assume constant speed of the sled
The FBD has horizontal forces as
60*cos(53)-(m*g-60*sin(53))*µk=0
solve for µk
µk=60*cos(53)/(m*g-60*sin(53))
j
2007-11-28 12:05:44 · answer #1 · answered by odu83 7 · 0⤊ 0⤋
huh? could have sworn I answered this. Oh well, here it is again.
since the sled is moving at constant velocity, it is not accelerating. therefore net forces along surface movement are zero.
so force of friction equals the horizontal component of the force on the rope
F = 60cos53
2007-11-28 20:32:34 · answer #2 · answered by Kevin 5 · 0⤊ 0⤋