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A smokestack deposits soot on the ground with a concentration inversely proportional to the square of the distance from the stack. With two smokestacks 20 miles apart, he concentration of the combined deposits on the line joining them, at a distance [x] from one stack is given by,

S = (k1/x^2) + (k2/[20-x]^2)

where k1 and k2 are positive constants which depend on the quantity of smoke each stack is emitting. If k1 = 7k2, find the point on the line joining the stacks where the concentration of the deposit is a MINIMUM.

2007-11-28 11:42:11 · 1 answers · asked by hello. 1 in Science & Mathematics Mathematics

help help help!

2007-11-28 12:39:59 · update #1

1 answers

Take the derivative of S and set it equal to 0. Use the fact that k1 = 7*k2, and you'll find that the answer does NOT depend on the actual value of k1, because k1 just factors out. The minimum obviously doesn't occur at an endpoint, because S goes to infinity at the endpoints. So where else can the minimum be? :)

2007-11-28 14:33:38 · answer #1 · answered by Curt Monash 7 · 0 1

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