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integrate: (x+1)(2x-3)/Sqrootx

2007-11-28 11:15:00 · 2 answers · asked by innerchild191 2 in Science & Mathematics Mathematics

and can u tell me how you worked it out plz?

2007-11-28 11:21:07 · update #1

2 answers

2x^2-x-3/x^2

2007-11-28 11:18:26 · answer #1 · answered by Anonymous · 0 0

(x + 1)(2x - 3) / x^(1/2) =
(2x^2 - x - 3)x^-(1/2) =
(2x^(3/2) - x^(1/2) - 3x^-(1/2)
∫[2x^(3/2) - x^(1/2) - 3x^-(1/2)]dx =
(4/5)x^(5/2) - (2/3)x^(3/2) - 6x^(1/2) =
((4/5)x^2) - (2/3)x - 6)√x + C

2007-11-28 11:58:27 · answer #2 · answered by Helmut 7 · 0 0

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