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The coordinates are : (0,3) (3,0). and then theres a line threw them. Can you tell me how pls ?? :)

2007-11-28 09:20:19 · 2 answers · asked by ? 2 in Science & Mathematics Mathematics

2 answers

The equation of a straight like is y = mx + b
where m is the slope and b is the y intercept

slope of the points (0,3) and (3,0) = (y1-y2)/(x1-x2)
(3-0)/(0-3) = -1

sub (0,3) in y = -x + b, b=3

so the eq is y=-x+3

2007-11-28 09:28:06 · answer #1 · answered by norman 7 · 0 1

try

x + y = 3
this way when x is 0, y is 3
and when y is 0, x is 3

now change it to standard format
y= 3 - x

2007-11-28 17:35:25 · answer #2 · answered by Clueless 5 · 1 0

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