A sample containing 24.09 grams of potassium, .308 moles of manganese, and 7.42 x 10^23 atoms of oxygen.?

Question

What is the empirical formula?What is the answer and how please

Answer 1

K = 24.09 / 39 = 0.618 moles
Mn = 0.308 moles
O = 7.42 x 10^23 / 6.022 x 10^23 = 1.23 moles
K:Mn:O :: 0.618:0.308: 1.23
Divide through by smallest ratio (0.308)
K : Mn : O :: 0.618/0.308: 0.308/0.308 : 1.23/0.308
K: Mn: O :: 2.01 : 1 : 3.99 (& approximate)

K: Mn : O :: 2 : 1 : 4
hence empirical formula is K2MnO4

Answer 2

in one molecule of CuSO4 there are 4 oxygen atoms, actual? Then, the question is, what proportion molecules incorporate 3.50 x 10^23 oxygen atoms? 3.50x10^23 / 4 = 8.seventy 5×10^22 So 8.seventy 5×10^22 molecules of CuSO4 incorporate 3.50 x 1023 oxygen atoms. in one molecule of CuSO4 there is one atom of sulfur, actual? Then in 8.seventy 5×10^22 molecules there are 8.seventy 5×10^22 atoms of sulfur. Now comes the straightforward area: what proportion moles is 8.seventy 5×10^22? all of us comprehend that one mole is 6.02×10^23. Then 8.seventy 5×10^22 / 6.02×10^23 = 0.14535×10^23 So there are 0.14535×10^23 moles of sulfur contained in a pattern of CuSO4 that still includes 3.50 x 10^23 oxygen atoms.

Answer 3

Safely & Permanently Remove Moles, Warts and Skin Blemishes