One interger is 8 less than another interger. The product of the lesser interger and -5 is 28 more than the greater interger. What are the interger?
2007-11-28 08:49:37 · 4 answers · asked by erikjjjacob 1 in Science & Mathematics ➔ Mathematics
a = b - 8
(-5)a = b + 28
(-5)(b-8) = b + 28
-5b + 40 = b + 28
-6b = -12
b = 2
a = 2 - 8 = -6
a = -6
b = 2
2007-11-28 08:54:25 · answer #1 · answered by mathguru 3 · 0⤊ 0⤋
x = y - 8
-5 * x = 28 + y
substuitute y - 8 for x in 2nd equation
-5 * (y - 8) = 28 + y
-5y + 40 = 28 + y
12 = 6y
2 = y
x = -6
2007-11-28 16:55:22 · answer #2 · answered by Jim L 3 · 0⤊ 0⤋
The integers are 2 and (-6). I did this by working with 7 as the larger integer, and slowly working my ay down. When i got to two, the smaller integer was (-6). (-6)*(-5) is 30. 30 - 2 = 28.
:-)
2007-11-28 16:56:54 · answer #3 · answered by rihim77 2 · 0⤊ 0⤋
Let x one integer, therefore the other one is x - 8
Then,
- 5 (x - 8) = x + 28
Solve for x,
x = 2
x - 8 = - 6
2007-11-28 16:55:39 · answer #4 · answered by achain 5 · 0⤊ 0⤋