Math question I need answered for tomorrow...?

Question

My math teacher posed this as a sort of challenge for us. Can anyone help me with it?
Starting from the general equation ax2 + bx +c =0. Come up with the quadratic equation for this equation by completing the square.
Thanks so much for any help!

Answer 1

The answer should be in your textbook anyway.
Here we go...

x^2 + (b/a)x + c/a = 0
x^2 + (b/a)x = -c/a
x^2 + (b/a)x + (b/2a)^2 = -c/a + (b/2a)^2
(x+b/2a)^2 = -4ac/4a^2 + b^2/4a^2
(x+b/2a)^2 = (b^2 - 4ac)/4a^2
x+b/2a = +/- sqrt(b^2-4ac)/2a
x = (-b +/- sqrt(b^2-4ac))/2a

Answer 2

Link

Answer 3

ax^2 + bx + c = 0
ax^2 + bx = -c
4a^2x^2 + 4abx = -4ac
4a^2x^2 + 4abx + b^2 = b^2 - 4ac
(2ax + b)^2 = b^2 - 4ac
2ax + b = +/- sqrt(b^2 - 4ac)
2ax = -b +/- sqrt(b^2 - 4ac)
x = [-b +/- sqrt(b^2 - 4ac)] / 2a

Answer 4

ax^2 + bx + c = 0

x^2 + (b/a)x + c/a = 0

x^2 + (b/a)x = -c/a

x^2 + (b/a)x + (b/2a)^2 = -c/a + (b/2a)^2

(x+b/2a)^2 = -c/a + b^2/4a^2

4a^2(x + b/2a)^2 = b^2 - 4ac

(x + b/2a)^2 = (b^2 - 4ac) / (4a^2)

x + b/2a = +/- sqrt((b^2 - 4ac) / (4a^2))

x + b/2a = +/- sqrt(b^2 - 4ac) / 2a

x = -b/2a +/- sqrt(b^2 - 4ac) / 2a


x = [-b+/- sqrt(b^2 - 4ac)] /2a

Answer 5

a=0
x=0
b=0
c=0
see?
0*0*2+0*0+0=0*2+0+0=0+0+0=0

Answer 6

i dont think you can solve this equation!Sorry!