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2007-11-28 07:13:48 · 4 answers · asked by smileyD 1 in Science & Mathematics Mathematics

4 answers

Will take a stab at:-
(x - 1) / 2 - (x + 3) / 3 = 7
3x - 3 - 2x - 6 = 42
x = 51

Tip
You must use brackets or question can mean anything.

2007-11-28 10:23:43 · answer #1 · answered by Como 7 · 2 1

I think i got the answer
96/16-1/2-24/4=3/3=7

btw, this is how i got it
half of 96/16 is 48/8
then half of that is 24/4
24/4 + 3/3 you have to find a LCD
the LCD is 12
which makes the fractions 72/12 + 12/12
72/12 is equal to 6 wholes and 12/12 is equal to 1 whole
6+1= 7
and that is how i found out the answer

2007-11-28 07:33:44 · answer #2 · answered by Rebecca S 2 · 1 1

3x² - 6x - 4 = 0 upload 4 to the two factors. 3x² - 6x - 4 + 4 = 0 + 4 group. (3x² - 6x) = 4 ingredient 3(x² - 2x) = 4 upload placeholders. 3(x² - 2x + ___) = 4 + 3(___) word that the 2d sparkling is expanded by using -3 to account for what you had to characteristic to end the sq.. Take the coefficient of the x term: -2 Divide it by using 2: -2 / 2 = -one million sq. it: (-one million)² = one million upload one million to the two blanks. 3(x² - 2x + one million) = 4 + 3(one million) x² - 2x + one million is the prolonged form of a suited sq. binomial. bear in techniques that (a - b)² = a² - 2ab + b². prepare this to what you have. 3(x² - 2x + one million) = 4 + 3(one million) 3(x - one million)² = 4 + 3(one million) Simplify something. 3(x - one million)² = 4 + 3 3(x - one million)² = 7 Divide the two factors by using 3. 3(x - one million)² / 3 = 7 / 3 (x - one million)² = 7 / 3 Take the sq. root of the two factors ?(x - one million)² = ?(7 / 3) x - one million = ± (?7 / ?3) upload one million to the two factors. x - one million + one million = one million ± (?7 / ?3) x = one million ± (?7 / ?3) x = one million(?3 / ?3) ± (?7 / ?3) x = (?3 / ?3) ± (?7 / ?3) x = (?3 ± ?7) / ?3 x = [(?3 ± ?7) / ?3](?3 / ?3) x = [?3(?3 ± ?7)] / [?3(?3)] x = [?3(?3) ± ?3(?7)] / 3 x = (3 ± ?21) / 3 answer: x = (3 ± ?21) / 3 examine utilising QUADRATIC formulation: Given: ax² + bx + c = 0 Quadratic formulation: x = [-b ± ?(b² - 4ac)] / 2a Given: 3x² - 6x - 4 = 0 ability: a = 3, b = -6, c = -4 x = [-b ± ?(b² - 4ac)] / 2a x = [-(-6) ± ?((-6)² - 4(3)(-4))] / 2(3) x = [6 ± ?(36 + (40 8)] / 6 x = [6 ± ?(80 4)] / 6 x = [6 ± ?80 4] / 6 x = [6 ± ?(4 * 21)] / 6 x = (6 ± 2?21) / 6 x = (3 ± ?21) / 3 real

2016-10-09 21:36:09 · answer #3 · answered by Erika 4 · 0 0

I dont understand the question, is that a minus sign? if so the X's cancel and the equation is not equal

2007-11-28 07:17:34 · answer #4 · answered by --Wedded--Bliss-- 3 · 0 0

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