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1. what is the cube rood of 9x?

2. (12 x^1/2y^-1 / 27 x^-1y^-1/3)^-1/2

2007-11-28 06:39:05 · 2 answers · asked by Kitz 1 in Science & Mathematics Mathematics

2 answers

(12/27)^(-1/2) = (4/9)^(-1/2) = 3/2
(x^1/2/x^-1)^(-1/2)= (x^3/2)^(-1/2)=1/x^(3/4)
(y^-1/y^-1/3)^(-1/2) = (y^-2/3)^(-1/2)=y^(1/3)

2. 3y^(1/3)/x^(3/4)


1. (9x)^(1/3)??

2007-11-28 06:47:48 · answer #1 · answered by norman 7 · 0 0

The cube root of 9x is 2.080083823 x

2007-11-28 14:49:17 · answer #2 · answered by Iced 2 · 0 1

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