English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

find the coefficient of x^3 in the boinomal expansion of (1+2x)^8

i got the answer as 56?

2007-11-28 06:10:35 · 2 answers · asked by Anonymous in Science & Mathematics Mathematics

2 answers

c(8,r) 1^(8-r) (2x)^r

8C(8,3)=8*6*7*8/6
Answer: 8*56=448

2007-11-28 06:24:41 · answer #1 · answered by iyiogrenci 6 · 1 0

yep u are right^^
should be equal to 8C3 which is 56
if u expend it:
1^8 + 8(1)x + 28(1)(x)^2 +56(1)(x)^3+...

2007-11-28 06:19:51 · answer #2 · answered by Optimist 2 · 0 1

fedest.com, questions and answers