for this kinda problem i just had to point out where the first mistake is made when the problem gets worked out. heres the rational expression.
problem: (6x)/(4y^2) times (y^3)/(x^2)
line 1[ (6x)/(4y^2) times (y^3)/(x^2) ]
line 2[ (6)/(4y^2) times (y^3)/(x) ]
line 3[ (6)/(4) times (y)/(x)]
line 4[ (6y)/4x) ]
which line did the mistake occur?
2007-11-28 05:26:22 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Line 2 is wrong. You must multiply both sides of Line 1 by 1/x in order to remove x from the left side of the equation.
The left side of line 2 is correct, but the right side should be
(y^3)/(x^3)
2007-11-28 05:31:36 · answer #1 · answered by Anonymous · 0⤊ 0⤋
right answer
try
(6x)/(x^2) times (y^3)/(4y^2) for clarity at line 2, okay
easier to follow
line 3 (6/x) times (y/4)
line 4 (6y)/(4x)
parenthesis missing in your line 4, before the 4x
2007-11-28 13:36:14 · answer #2 · answered by Jim L 3 · 0⤊ 0⤋
Line 2 bro
2007-11-28 13:32:55 · answer #3 · answered by Anonymous · 0⤊ 0⤋
I can't tell where the square went from the x. did you take the square root of both sides??
2007-11-28 13:34:59 · answer #4 · answered by shrddrshrty 3 · 0⤊ 0⤋
(6x / 4 y*y) * (y*y*y / x*x) =
(cancel x's both sides)
(6 /4 y*y) * (y*y*y / x) =
(cancel y's b. s.) =
(6/4) * (y/x) =
6*y / 4*x [answer].
2007-11-28 13:45:07 · answer #5 · answered by BB 7 · 0⤊ 0⤋
i found no error
2007-11-28 13:32:22 · answer #6 · answered by Tuan@GGHS 2 · 0⤊ 0⤋