so far all i have is f(1/4)= log2^1/4
2007-11-28 04:05:12 · 4 answers · asked by ALF 2 in Science & Mathematics ➔ Mathematics
log2(1/4)=log2(1)-log2(4) --- Quotient rule
--- log2(1)=0 --- Log(1) with a base of anything is 0, because anything^0=1
--- log2(4)=y --> 2^y=2^2 --> y=2 --- if a^x=a^y then x=y
0-2= -2, which is the answer
2007-11-28 04:23:01 · answer #1 · answered by someone2841 3 · 0⤊ 0⤋
If y = log (base 2) (1/4), then 2^y = 1/4
Change it to 2^y = 2^ (-2)
y = -2
So f(1/4) = -2
2007-11-28 12:11:18 · answer #2 · answered by chcandles 4 · 0⤊ 0⤋
f(x)=log2^x at x=1/4is
f(1/4)=log2^(1/2)^2
=2log2^2^(-1)
= -2log2^2
= -2.1
= -2
2007-11-28 12:17:02 · answer #3 · answered by rajesh v 2 · 0⤊ 0⤋
log to base 2 ( 2 ^-2 )= - 2 .
2007-11-28 12:13:33 · answer #4 · answered by drmobaid 2 · 0⤊ 0⤋