is this factor able? algebra1?

Question

2x^2-3x-9

Answer 1

Yep

(2x + 3)(x - 3)

Answer 2

Yes.

(2x + 3)(x - 3)

When I was taking alebra I had a hard time with these. The first two of each ( ) was easy for me, but the second set of numbers always stumped me. The way I figured them out was this: Figure out your factors of the last number (ie 9 = (9*1) or (3*3)) Then plug them into your trinomial factor layout and use foil and trial and error to find the right one.

Here is another good tool:
http://www.algebrahelp.com/lessons/factoring/trinomial/

I like this website better though:
http://regentsprep.org/Regents/math/factor/Ltri1.htm

And to check your work here is an online factoring calculator. Just plug in the trinomial and it will factor it for you,..... But please don't neglect learning how to do it yourself. Please only use this as a tool to check yourself if you need to.
http://www.algebrahelp.com/calculators/expression/factoring/

Good luck with your homework, hun!

Answer 3

It actually is if you use a little trial and error:

It comes to (2x+3)(x-3)

You can check: If you FOIL, you get: 2x^2+3x-6x-9 or 2x^2-3x-9

Answer 4

ax^2+bx+c
Find the discriminant: b^2-4ac and check whether if it is a perfect square.

2x^2-3x-9
a=2
b=-3
c=-9

b^2-4ac
(-3)^2-(4)(2)(-9)
9+72
81


81 is perfect square therefore it is factorable










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Answer 5

(2x+3)(x-3)
extention:u can always find the answer by using the quadractice equation x=(-b±√(b^2-4ac))/2a.

Answer 6

Yes it's factorable.

By trial and error or by using quadratic equation you can get its factors..

Answer 7

(2x + 3)(x - 3)

Answer 8

first of all, the word is "factorable," please check your spelling. second, you can make it

(2x+3)(x-3)

Answer 9

its doable but what is ^ ? oh and what does x represent?

Answer 10

No!