3 ( x + 5 ) ² = 48
( x + 5 ) ² = 16
( x + 5 ) = ± 4
x = - 1 , x = - 9
2007-11-28 01:25:49
·
answer #1
·
answered by Como 7
·
4⤊
2⤋
If you look at the power of this question...it's a quardratic equation, so there should be 2 answers.
3 (x+5)^2 - 7 = 41
3 (x^2 + 10x + 25) - 7 = 41
3x^2 + 30x + 27 = 0
3 (x^2 + 10x + 9) = 0
x = -1 or/and x= -9 .
2007-11-27 17:00:27
·
answer #2
·
answered by scholachu 3
·
0⤊
1⤋
I think x = - 9 is the second answer.
3(x + 5)^2 = 48
Divide both sides by 3......(x+ 5)^2 = 16
(x + 5)^2 - 16 = 0 Difference of squares.
So solve as such. [(x + 5) - 4][(x + 5) + 4]
(x + 1) = 0 (x + 9) = 0
x = -1 and -9
2007-11-27 17:01:50
·
answer #3
·
answered by huckleberry 5
·
0⤊
0⤋
(x + 5)^2 = x^2 + 10x + 25
3x^2 + 30x + 75 - 7 = 41
3x^2 + 30x + 75 - 48 = 0
3x^2 + 30x + 27 = 0
x^2 + 10 + 9 = 0
x^2 + 9x + 1x + 9 = 0
x(x + 1) + 9(x + 1) = 0
(x + 9)(x + 1) = 0
x = -9 or x = -1, so yes there is another answer. In a quadratic equation, with x^2 as the highest term, you should always expect two answers.
2007-11-27 16:55:39
·
answer #4
·
answered by Edgar Greenberg 5
·
0⤊
1⤋
add seven to both sides
3(x+5)^2 = 48
divide by 3
(x+5)^2 = 16
square root (both positive and negative)
x + 5 = +/- 4
x = 4 - 5
and
x = -4 - 5
x = -1 and -9
2007-11-27 16:52:53
·
answer #5
·
answered by Jay 4
·
1⤊
0⤋
3(x+5)² - 7 = 41
3(x+5)² = 48
(x+5)² = 16
x + 5 = ±4
x + 5 = 4, x = -1 ....... OR
x + 5 = -4, x = -9
2007-11-27 16:52:59
·
answer #6
·
answered by Philo 7
·
1⤊
1⤋
Since the highest x factor you have is squared, then there are two answers. Distribute first then solve.
3x^2+30x+75-7=41
3x^2+30x+27=0
3(x^2+10x+9)=0
3[(x+9)(x+1)]=0
(x+9)(x+1)=0
x+9=0 and x+1=0
So x=-9 and x=-1
Then check to verify.
2007-11-27 17:02:27
·
answer #7
·
answered by BB 1
·
0⤊
1⤋
Yes, there are multiple answers.
(x+5)^2 = 16
Which means that:
x+5 = +/- 4
So, x can be -1 or -9.
2007-11-27 16:54:06
·
answer #8
·
answered by niki 2
·
1⤊
0⤋
all the answers above are right but keep in mind that if the leading term is to the second power THERE WILL ALWAYS BE EXACTLY TWO ANSWERS. just wanted to provide emphasis.
2007-11-27 17:01:29
·
answer #9
·
answered by flkasdjflkasdj;lrf 3
·
0⤊
1⤋