Solve by factoring: x^2 +3x - 18 = 0?

Question

Solve by factoring: x^2 +3x - 18 = 0? can you also show me the steps by which you arrived at your answer?

Answer 1

(x******)(x*****) = 0
(x*****6)(x****3) = 0
(x + 6 )(x - 3) = 0
x = - 6 , x = 3

Answer 2

Solve by factoring: x^2 +3x - 18 = 0

(x+ 6) (x - 3) = 0
x+ 6 = 0 means that x must be -6 since -6 +6 = 0
or
x-3 =0 means that x must be 3 since 3-3 = 0

Steps: Since the coefficient of the x^2 term is 1, look for the factors of -18 (last term) whose sum is +3 (since +3 is the coefficient of the middle term.) Remember the factors of -18 are +1 and -18 (sum is -17), -1 and +18 (sum is +17), +2 and -9 (sum is -7), -2 and +9 (sum is +7), +3 and -6 (sum is -3), and -3 and +6 (sum is +3; therefore you want to use the factors listed above each set to 0 and solve.)

Answer 3

x^2+3x-18=0
-18 tells you that the signs in parenthesis will be +,- or vice versa.
so (x+_) (x-_)=0
to get your numbers, you have to find two numbers that multiply and become 18, but can be added to make the number 3.
so (x+6) (x-3)=0
because 6*-3=18 and 6+(-3)=3
then to get your factors you subtract each value from 0.
so x+6=0, therefor x=-6 and x-3=0, therefor x=3

so the answer is -6,3

Answer 4

factor out 18*1
1*18
2*9
3*6

Now find which one on the list multiplies to -18 and adds to 3.
-3 and 6

Now factor by grouping.
x^2-3x -6x-18
Take out an x in x^2-3x. You will get x(x-3)
Take 6 out of the second half -6x-18. You will get 6(x-3)

Now that the outsides of the two (x+6) then (x-3)

Answer 5

x^2 +3x - 18 = 0
(x-3)(x+6)=0
x-3=0 x+6=0
x=3 @ x=-6

Answer 6

Solve 3x 18

Answer 7

x^2+3x-18 =
= x^2 + (6x - 3x) -18
= (x^2 + 6x) - (3x + 18)
= x(x+6) - 3 (x+6)
= (x+6) (x-3)
so we have successfully factorised the given equation.
so the answer will be:
x^2+3x-18 = (x+6) (x-3) = 0
so: either (x+6) = 0 OR (x-3) =0
so: either x= (-6) OR x = (+3)
so: x ={3, -6} is the final answer.

Answer 8

(x+6)(x-3) roots are -6, 3

find factors of 18 and see which add up to 3

then set each to zero:
(x+6)=0, (x+3)=0 and solve for x

Answer 9

1x2=2+3=6x3=18-18=0

Answer 10

you can factor the equation into:
(x+6)(x-3)=0
set each factor equal to 0 and solve
x+6=0
x= - 6
and
x-3=0
x=3

Answer 11

2 numbers that multiply to -18 and add to 3 That would be...
-6 and 3.

Next you have this (x-6)(x+3)
Now x-6=0 and we gotta isolate for x so..
x=6 by bringing the 6 over

x+3=0
x=-3

And so there ya have it, x= -3, and 6