What is the acceleration of a vehicle that changes its velocity from 85 km/h to a dead stop in 14 s?

Question

how do you solve it? and what is the final answer?

Answer 1

its acceleration=velocity/time
so 85/14
so 6.071428571 or round it to 6.07km/h
but since your stopping its negative
so -6.07km/h

check it using the formula its also on the link

Answer 2

Acceleration is defined as final velocity minus initial velocity all over the time.

a = (vf-vi)/t
a = (0 - 85 km/h) /14 s

**85 km/h is 23 11/18 m/s

a = (- 23 11/18 m/s) / 14 s
a = -1.6865 m/s^2

The vehicle decelerated.

Answer 3

v = vo + at

v = final velocity (zero)
vo = initial velocity ( 85 km / h )
a = acceleration (what you need)
t = time (14 s )

Convert vo into meters per second and solve for a.

vo = ( 85 km / h ) ( 1 h / 3600 s ) ( 1000 m / km )

Answer 4

well lets convert 85km/h into m/s.

85km/h = 23.6 m/s
v1 = 23.6 m/s
v2 = 0.0m/s
time = 14 s
a = ?
now acceleration = (v2 - v1)/ time

a = (v2-v1)/ time
a = (0.0m/s - 23.6m/s) / 14 s
a = -23.6 m/s / 14 s
a = -1.7 m/s^2

this is negative because the car is slowing down.