Okay, so here's the problem, and I've tried EVERYTHING. I just don't understand it!
How much force do you need apply to the (horizontal) top of a box to push it over?
The box is 27kg, is 1.3 m tall and is .83 m long. Any help?
2007-11-27 14:21:40 · 4 answers · asked by motelman94 1 in Science & Mathematics ➔ Mathematics
I will be happy to help you. To tip the box it must pivot about its bottom corner. If the box is uniformly loaded then its center of gravity is halfway along the .83 m edge. So to tip it you must overcome a resistive torque of (1/2) X (.83 m) X (27 Kg.). Then to overcome it you will apply a force F at a moment arm distance of 1,3 m. So set 1.3 X F equal to the resisting torque.
2007-11-27 14:46:16 · answer #1 · answered by Tim C 7 · 0⤊ 0⤋
i think this is not a match question, is a Science question
2007-11-27 22:25:01 · answer #2 · answered by kehado 1 · 1⤊ 0⤋
I think this is more physics than math..
2007-11-27 22:24:47 · answer #3 · answered by 港式奶茶 3 · 1⤊ 0⤋
I cant solve it.Very hard
2007-11-27 22:28:45 · answer #4 · answered by Patrick N 2 · 0⤊ 1⤋