PLEASE HELP!!!!!!!!! PHYSICS. plEase!?

Question

A 0.590 kg wood block is firmly attached to a very light horizontal spring (k = 200 N/m) as shown in Fig. 6-40. It is noted that the block-spring system, when compressed 5.0 cm and released, stretches out 2.3 cm beyond the equilibrium position before stopping and turning back. What is the coefficient of kinetic friction between the block and the table?

Answer 1

The energy stored in the spring is
.5*k*x^2
when compressed
.5*200*(5/100)^2
when elongated
.5*200*(2.3/100)^2

the difference is the energy lost to friction for the block to slide 7.3 cm

the energy of friction is
0.590*9.81*µk*7.3/100
solve for µk

µk=0.466

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