please help me in my algebra homework?

Question

A famer has dogs and chikens. Hi dogs and chickens have a total of 148 legs and 60 heads. HOW MANY DOGS AND HOW MANY CHICKENSDOES THE FARMER HAVE?

i started with:

c=chickens
d=dogs

2c+4d=148 &
c+d=60


plz help and show work.

plz and ty.

Answer 1

2c+4d=148
c+d=60

c=60-d
2(60-d)+4d=148
120-2d+4d=148
120+2d=148
2d+120-120=148-120
2d=28
d=14

c+14=60
c+14-14=60-14
C=46
46 chickens and 14 dogs

Answer 2

Solve second equation for either c or d. I like dogs better (kinda scared of chickens) so I will kill off the chickens (hehehe)

c = 60 - d

Substitute "60 - d" in the first equation wherever you have a "c."

2(60 - d) + 4d = 148
120 - 2d + 4d = 148
120 + 2d = 148
2d = 28
d = 14

c + d = 60
c + 14 = 60
c = 46

Check your work....

2(46) + 4(14) = 148
92 + 56 = 148
148 = 148 Woohoo!!!!

46 chickens and 14 dogs. Great problem except for the dogs are outnumbered by the stoopid chickens.

Answer 3

c=chickens
d=dogs

2c + 4d = 148
c + d = 60

solve for one of the animals:

i'm going to solve for c...

2c = 148 - 4d
(2c)/2 = (148 - 4d)/2
c = 74 - 2d

then replace C in your second equation...

c + d = 60
(74 - 2d) + d = 60
74 - 2d + d = 60
74 - d = 60
- d = 60 - 74
-d/-1 = -14/-1
d = 14

replace d with 14.

c + d = 60
c + 14 = 60
c = 60 - 14
c = 46

check your work with the legs...

2 (46) + 4(14) = 148
92 + 56 = 148

Answer 4

-4c - 3c = 22 - 36 -7c = -14 c = 2 4g/14 - g/14 = 3/14 + 3/7 3g/14 = 3/14 + 6/14 = 9/14 3g = 9 g = 3 3r/4 = 5/6 - 2/3 3r/4 = 5/6 - 4/6 3r/4 = a million/6 9r/12 = 2/12 9r = 2 r = 2/9 6x = 25 + 86 = 111 x = 111/6 x = $18.50

Answer 5

d=60-c
2c+4(60-c)=148
2c=92
c=46
d=14