Can you write 42/45 with prime numerators and denominators????

Question

you can use as many fractions as you wish....... this is a big math problem for me and i cant seem to figure it out so can i have some help pleas??

Answer 1

Let's try....
42 = 21*2 = 7 * 3 * 2
45 = 9 * 5 = 3 * 3 * 5

One set of threes reduces out. We are left with numerators of 7 and 2 and denominators of 3 and 5. Since you specify that the numerators and denominators must be prime, we can't multiply the numerators together and the denominators together (or they won't be prime anymore). HOWEVER, we can write this as a multiplication problem:

(7 over 3) times (2 over 5).

Now everything is prime!

Hopefully, that is what you are looking for.

Answer 2

Actually no because if you write the prime factors of both you can see that for 42 it is 3 times 2 times 7. For 45 is 3 times 3 times 5 and you cancel out 1 set of three and for the remaining numbers multiply 7 times 2 equals 14 for the numerator and 3 times 5 wich equals 15 so as yuo can see it is 14/15 which 14 is not prime That is easy

Answer 3

I sure can! And so can you if you take the time and go back and read your book like a good girl. Do your own homework, or it will come back to bite you when you can't do anything for yourself when you are grown up.