The sun has a diameter of 870,000. The earth a diameter of 8,000mi. If a 24 cm diameter basketball is used as the model for the sun, what should be the diameter of the model earth?
2007-11-27 12:09:05 · 9 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
.22069
2007-11-27 12:14:27 · answer #1 · answered by Gatsby216 7 · 0⤊ 0⤋
Just set up a proportion: ratio of diameters of sun to earth equals ratios of diameters of models of sun to earth:
870,000/8000 = 24/d and solve for d, diameter of earth model, by cross multiplying.
2007-11-27 12:13:45 · answer #2 · answered by baja_tom 4 · 1⤊ 0⤋
24 cm = 8000 miles
8000 miles = 24 cm
1 mile = 24/8000 cm
870,000 miles = (24/8000)(870,000)=2610 cm
2007-11-27 12:19:19 · answer #3 · answered by cidyah 7 · 0⤊ 0⤋
This is a basic ratio.
870,000 is to 24cm as 8000 is to X
Cross multiply.
8000 x 24 / 870,000 = .22cm
2007-11-27 12:14:05 · answer #4 · answered by lvscottt 1 · 0⤊ 0⤋
870/8 = 24/x
870x=8(24)
x=192/870=?
use a calculator
2007-11-27 12:13:34 · answer #5 · answered by RickSus R 5 · 1⤊ 0⤋
something approximately 1/4 of 1 cm in diameter......the only thing i can think of is a pea
2007-11-27 12:15:19 · answer #6 · answered by smart mike 2 · 0⤊ 0⤋
24/870000 = x/8000
x=8*24/870 = 0.22 cm=2.2mm
2007-11-27 12:14:02 · answer #7 · answered by tinhnghichtlmt 3 · 1⤊ 0⤋
x/24 = 8000/870000
x = 192000/870000 = .2207 cm
2007-11-27 12:15:52 · answer #8 · answered by holdm 7 · 0⤊ 0⤋
2610
2007-11-27 12:12:50 · answer #9 · answered by HI!!!!!! 3 · 0⤊ 3⤋