the second of three numbers is 2 more than the first. The third exceeds the second by 2. Find the three #?

Answer 1

1,3,5

Answer 2

Let x = the first number
x + 2 = the second number
x + 4 = the third number

Is this all we know? Don't you have their sum or anything? We can't get an equation and know exactly what the numbers are from the little information you gave. Example, the numbers could be 1, 3 and 5 or they could be 20, 22, 24 -- there's an infinite amount of trios they could be.

Answer 3

The answer is 5.
Your first number is 1
Second number is 3 (that's 2 more than the first)
Third number is 5 ( exceeds the second by 2)

Answer 4

Well, there are many combinations, so you need to add more detail. From what you're saying, i think you mean that the third is two more than the second, which is two more than the first... so it could be 1,3,5, or 9999991, 9999993, 9999995. Add more detail, otherwise there is not enough information. Any number sequence where the number left of a number is two less than it.

Answer 5

According to the given conditions
The first Number = x ( assume )
The second number = 2x
and the third number = 2x+2

Now give any value to x, you will get the required sequence. There are infinite number of solutions.

Answer 6

I think you've left something out, like a sum of the three or something. As vague as it reads now, any group of numbers would answer it.

1-3-5
2-4-6
11-13-15

etc, etc, etc...

Answer 7

024, 135, 246, 357, 468, 579 (these are your only possiblities assuming your are only using single whole digits)

Answer 8

x
x+2
x+4

substitue any number for x. unlimited possibilities