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2007-11-27 11:46:45 · 1 answers · asked by Anonymous in Science & Mathematics Physics

A car is traveling east with a mass of 1200kg and a truck is traveling north with a mass of 2100kg, after the collision, they move together with a distance with a distance of 17m at an angle of 83 degres from the horizontal in an intersection, they both have the same final velocity. The width of the road is given to be 6.0m. What is the final velocity of both the vehicles? What are the initial velocities of the car? Which vehicle (s) stopped at the stop signbefore proceeding to the intersection?

2007-11-27 11:54:35 · update #1

1 answers

Using conservation of momentum in the horizontal and vertical
1200*vc=3300*cos(83)*vf
2100*vt=3300*sin(83)*vf
vc is speed of the car and vt is the speed of the truck, vf is there speed together.
tan(83)=1.75*vt/vc
vt/vc=4.65

The truck was moving much faster.

In order to compute the speeds I need the µk for the crashed vehicles.

let's see if it can be derived
the work done by friction is
3300*9.81*µk*17

that is equal to
.5*3300*vf^2
2*9.81*17*µk=vf^2

now we have three equations and four unknowns

Let's assume µk=0.8 and solve
vf=18.26 m/s
vc=6.12 m/s
vt=28.5 m/s

j

2007-11-30 12:58:17 · answer #1 · answered by odu83 7 · 0 0

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