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A 202-kg crate is pushed horizontally with a force of 709 N. If the coefficient of friction is 0.20, what is the acceleration of the crate?

2007-11-27 11:27:51 · 1 answers · asked by Anonymous in Science & Mathematics Physics

1 answers

Net force equals mass time acceleration
The net force is 709 minus friction

friction is
202*9.8*0.20
therefore
709-202*9.8*0.20=202*a
solve for a
a=1.55 m/s^2

j

2007-11-28 05:11:52 · answer #1 · answered by odu83 7 · 0 0

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