this is the problem:
n(5n-2)(2n+5)=0
Does anybody know how to solve this?
The lesson is Solving Equations by Factoring
2007-11-27 11:14:30 · 5 answers · asked by Anonymous in Education & Reference ➔ Homework Help
You have three factors, and to get a product of zero, one of them has to equal zero. So, either n=0, or 5n-2=0, or 2n+5=0. Only the second and third one have to be worked on to get a value for n. If 5n-2=0, then 5n=2 (add 2 to both sides), and n = 2/5 (divide both sides by 5). If 2n+5=0, 2n=-5 (subtract 5 from both sides), and n = -5/2 (divide both sides by 2). There are your three possible values for n, 0, 2/5, or -5/2. OK?
2007-11-27 11:24:30 · answer #1 · answered by TitoBob 7 · 0⤊ 0⤋
anything multiplied by 0 will equal 0, this equation is using the same principle but working backwards
you have three number (n) (5n-2) and (2n+5) multiplied to get 0, that means either n = 0, 5n-2 = 0 or 2n+5 = 0
solving these three equations you get n = 0, n = 2/5, or n = -5/2
2007-11-27 19:21:32 · answer #2 · answered by dohboy000 4 · 1⤊ 0⤋
2n+5=0
2007-11-27 19:26:34 · answer #3 · answered by Anonymous · 0⤊ 0⤋
All you need is to use distributive property.
2007-11-27 19:23:30 · answer #4 · answered by lt.unholy_darkness 2 · 0⤊ 1⤋
i do not know butthat sound and looks really hard
2007-11-27 19:21:47 · answer #5 · answered by Anonymous · 0⤊ 1⤋