Hopping into your car, you floor it and accelerate at 9.1 m/s^2 without spinning the tires. Determine the minimum coefficient of static friction between the tires and the road needed to make this possible.
Please show/explain all work clearly please!
2007-11-27 10:35:13 · 3 answers · asked by nirmal 1 in Science & Mathematics ➔ Physics
We make the usual unrealistic assumptions, treat the car as a point mass, and so on. The normal force N = mg so the static friction force is umg where u is the coefficient of static friction.
Newton's Second Law is F = ma
umg = ma
ug = a
u = a / g = 9.1 / 9.8
2007-11-27 10:40:02 · answer #1 · answered by jgoulden 7 · 1⤊ 0⤋
(PhD Physicist responds)
F=ma
F=mu mg (normal force times coefficient of friction)
so ma = mu mg or
a = mu g (note does not depend on mass of the car)
g = 9.8m/s2
a = 9.1m/s2
solve for mu
2007-11-27 18:42:26 · answer #2 · answered by banjoman 6 · 0⤊ 0⤋
I am not going to answer this question, and I encourage others not to do so as well. The asker is just trying to get us to do his homework for him. Asker, in the future you should attempt to solve the problem yourself and tell us what you have done so far, so we can see that you are at least trying.
2007-11-27 18:40:28 · answer #3 · answered by Anonymous · 0⤊ 1⤋