how do u solve for this?

Question

sqrt ( 4n^2+3n+3) -2n * sqrt (4n^2+3n+3) +2n ...how does it simplify to 3n+3?

Answer 1

[sqrt ( 4n^2+3n+3) -2n ]* [sqrt (4n^2+3n+3) +2n]
= 4n^2+3n+3 - 4n^2
= 3n+3
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Ideas: a^2-b^2 = (a-b)(a+b)

Answer 2

This is in the form of (x - y )(x + y)
which expands to x² - y²

using the same approach
sqrt (( 4n²+3n+3) -2n)( sqrt (4²+3n+3) +2n)

( 4n² + 3n + 3) - 4n²

after combining terms, what remains is

3n + 3
.

Answer 3

Take another look at the problem. It is composed of the factors from a difference of squares! So for the first terms, if you square the square root of any thing you get that term thus the first term is (4n^2 + 3n + 3) and the second term is -4n^2. Added together you get 3n+3

Answer 4

Remember the formula(a+b) x(a-b)= a^2 - b^2

Then the product is (4n^2+3n+3) - 4n^2= 3n + 3.

Not difficult !

Answer 5

FOIL > multiply the First then the Outer, Inner, and finally the Last set of the problem. Remember that a sqrt times another sqrt equals the number in side that sqrt.