how do you factor t2+18t+81?

Question

im factoring trinomials in algebra II and I need major help

Answer 1

College Method:

Find two factors of 81 that add up to 18.
The factors are 9 and 9.
Rewrite equation as t^2+9t+9t+81
Group t^2+9t and 9t+81
Rewrite as t(t+9)+9(t+9)
Rewrite as (t+9)(t+9)
Simplify as (t+9)^2

Perfect Square Method:
If you recognize that the first and last two terms are perfect squares (which this is) you can use this method.
First write the square root of the first (t) and the last (9)
Seeing that the middle term is positive, the sign joining t and 9 is positive.
Therefore, (t+9)^2

Answer 2

this expression is in the format ax2+bx=c (i'll use the variable when i explain it). so.

first you find the factor of 'ac' that have a sum of 'b' (in this case 9 and 9). then you divide both numbers by 'a' (in this case you still have 9 and 9). you then add each number to 'x' in a separate parentheses. so the answer is (x + 9)(x + 9).

Answer 3

(t+9)^2

(t+9)(t+9)

Answer 4

(t + 9) (t+9)

Answer 5

ummm... i think

t(2+18) + 81
t(20) + 81
20t + 81


idk..?