x^2-22x+121 factor out the trinomial?

Answer 1

x^2-22x+121

(x - 11)(x - 11)
.

Answer 2

With factoring you know that the two factors of c in y=x^2+bx+c must add to b.
The factors of 121 are 1,11, and 121 and -1, -11, -121. Obviously 1, 121, -1, -121, could not ever add up to -22 no matter how they are multiplied together to get to 121. Therefore, 11 positive or negative only works. Since, 22 is negative, since -11x2 is -22, and since -11x-11 is 121, you have your answer.
(x-11)(x-11) or (x-11)^2
This can be more easily remembered as a general rule as follows:
if
y=x^2-2ax+a^2, then it factors as (x-a)(x-a) or (x-a)^2.

Answer 3

Hmmmm the way I've learned to do this is to find two numbers that multiply to the last number and that add to the first one

-11, and -11 do just that

So your factors are

(x-11)^2 = (x-11)(x-11)

Answer 4

x^2-22x+121
x^2-11x-11x+121
x(x-11)-11(x-11)
(x-11)(x-11)
x=11