is it -e^(-1)
2007-11-27 06:44:28 · 4 answers · asked by PDF 2 in Science & Mathematics ➔ Mathematics
i meant e^(-x) sorry
2007-11-27 06:54:12 · update #1
e^(-1) is a constant. It would go outside the integral, so int(e^(-1)dx) = e^(-1)x + C, which is x/e + C.
int(e^(-x)dx) = -e^(-x) + C
2007-11-27 06:47:29 · answer #1 · answered by Edgar Greenberg 5 · 2⤊ 1⤋
Remember, since e^(-1) is a constant (lets use K to represent constant), the antiderivative of any constant, K, is: Kx+C. So, plugging the e^(-1) in, we get: e^(-1)x+C
2007-11-27 06:49:27 · answer #2 · answered by Enrique 2 · 0⤊ 1⤋
And did you also mean to say "is it -e^(-x)"? That's a little better, but now you forgot the constant.
2007-11-27 08:07:57 · answer #3 · answered by Tony 7 · 0⤊ 0⤋
This is undoubtedly the worst question I have ever seen. There is no variable. The integral would have to be:
C ± x/e
2007-11-27 06:47:09 · answer #4 · answered by Dr D 7 · 1⤊ 3⤋