2007-11-27 05:59:10 · 8 answers · asked by bn4real2000 1 in Science & Mathematics ➔ Mathematics
20x^2 + 33x + 10=0
20x^2 + 25x + 8x + 10 = 0
5x(4x + 5) + 2(4x + 5) = 0
(5x + 2)(4x + 5) = 0
5x + 2 = 0 or 4x + 5 = 0
5x = -2 or 4x = -5
x = -2/5 or x = -5/4
2007-11-27 06:04:30 · answer #1 · answered by ben e 7 · 0⤊ 0⤋
20x^2+33x+10=0
(5x +2)(4x +5) =0
x = -2/5 or -4/5
2007-11-27 14:05:50 · answer #2 · answered by David F 5 · 0⤊ 0⤋
(4x+5)(5x+2)=20x^2+8x+25x+10=20x^2+33x+10
x= -2/5 and -5/4
2007-11-27 14:08:54 · answer #3 · answered by MoneyMatt 4 · 0⤊ 0⤋
20x^2+33x+10=0
20x^2+25x++8x+10=0
5x(4x+5)+2(4x+5)=0
(4x+5)(5x+2)=0
so
4x+5=0
4x=-5
x=-5/4
or
5x+2=0
5x=-2
x=-2/5
so the value of x is either -5/4 or -2/5
2007-11-27 14:05:05 · answer #4 · answered by Siva 5 · 0⤊ 0⤋
factor it to: (4x+5)(5x+2)=0
solutions must be 4x+5 = 0 or 5x+2=0
so x= - 5/4 or x = -2/5
2007-11-27 14:04:51 · answer #5 · answered by Shredded Cottage Cheese 6 · 1⤊ 0⤋
(5x+2)(4x+5)=0
5x+2=0
4x+5=0
5x=-2
4x=-5
x= -2/5 or - 5/4
2007-11-27 14:05:05 · answer #6 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋
(5x + 2)(4x + 5)
2007-11-27 14:05:11 · answer #7 · answered by Justin 2 · 0⤊ 0⤋
What is the question?
2007-11-27 14:01:03 · answer #8 · answered by Pascal 4 · 0⤊ 3⤋