Algebra Help!?

Question

1. The weight of two beluga whales and three orca whales totals 36,000 pound. The weights of one of the belugas and one of the orcas add up to 13,000 pounds. Using this information, how much do the belugas weight? What about the orcas?

2. Write a system of equations for this problem.

3. Solve it by substitution.

4. Solve by the addition method.

Answer 1

represent the given:

B - whales
O- orcas

then set-up the equations:

(1) 2B+3O=36000 (got it? 2 whales + 1 orca = 36000 pounds)
(2) B+O=13000

solving it by substitution, using 2,

B=13000-O and plugging this to 1, (let's call this 3)

2(13000-O)+3O=36000
26000-2O+3O=36000
thus, O=10000
and B (going back to 3)=3000

Solving it by elimination,
(1) 2B+3O=36000
(2) B+O=13000

multiplying (2) by -2, we get -2B-2O=-26000 (let's call it 4)

add (1) and (4),

O=10000, plugging it to (1)
2B=36000-30000
B=3000

hope this helps! =)

Answer 2

Let B be the weight of a beluga whale and C the weight of an orca whale.

"The weight of two beluga whales and three orca whales totals 36,000 pounds."

3B + 2C = 36000

"The weight of one beluga whale and one orca is 13,000 pounds."

B + C = 13000

Create a substitution using the second equation...

B = 13000 - C

...and substitute into the first...

3B + 2C = 36000
3 ( 13000 - C ) + 2C = 36000

Now solve for C, then use any of the first equations to find B.

Or you can solve using the addition method:

3B + 2C = 36000
B + C = 13000

Multiply the entire bottom equation by -2

3B + 2C = 36000
-2B -2C = -26000

Now add the equations. The 2C and -2C terms go away; solve the result for B.

3B - 2B + 3C - C = 36000 - 26000
B = 10000

Now you can find C.

Answer 3

2 beluga + 3 orca=36000
1 beluga + 1 orca=13000

Multiply the 2nd equation by 2
2 beluga + 2 orca=26000
Subtract from the first equation
1 orca = 10000
Substitute 10000 in 2nd equation
1 beluga + 10000=13000
1 beluga = 3000

Answer 4

Beluga=B; Orca=R

2B + 3R = 36000
B + R = 13000.

That's your two equations. The rest you can do yourself. How else would you learn if you keep asking others to do your work?

Answer 5

Let the weight of beluga be x
let the weight of orca be y

2x+3y=36000 let this be equation 1
x+y=13000 let this be equation 2
x=13000-y

substitute this value of x in equation 1
2x+3y=36000
2(13000-y)+3y=36000
26000-2y+3y=36000
-2y+3y=36000-26000
y=10000

so the weight of the orca is 10000
so the weight of the beluga is
x+10000=13000
x=13000-10000
x=3000

verify now
so
2*(3000)+3*(10000)=6000+30000=36000
so the answer is right

Answer 6

Beluga = x, Orca = y

2x + 3y = 36,000

x + y = 13,000

x + 2y = 23,000

y = 10,000

x = 3,000

Answer 7

let the weight of beluga whale = x

weight of orca whale = y

with the given information we can frame two equations

2x + 3y = 36,000 -----------------------eqn(1)

x + y = 13,000--------------------------eqn(2)

from eqn(2) = x = 13000 - y ----------------eqn(3)

substituting in eqn(1)

2(13000 - y) + 3y = 36,000

26000 - 2y + 3y = 36000

y = 36000 - 26000 = 10,000

substitute y value in eqn(3)

x = 13,000 - 10,000 = 3,000

addition method

multiply eqn(2) with 2

2x + 2y = 26,000 ----------------------eqn(4)

subtract eqn(4) from (1)

y = 10,000

substitute y value in eqn(2)

x + 10,000 = 13,000

x = 13,000 - 10,000 = 3,000

Answer 8

For increasing cubic binomials the final formula is as follows: (a + b) ^ 3 = a^3 + 3*a^2*b^one million + 3*a^one million*b^2 + b^3 on your case, a is x and b is -y^5 So (x - y^5)^3 = x^3 + 3*x^2*(-y^5)^one million + 3*x^one million*(-y^5)^2 + (-y^5)^3 Simplified: =x^3 - 3x^2*y^5 + 3x*y^10 - y^15 :D

Answer 9

cheating is wrong

oh em gee

if you cheat or if you dont do your work yoursef how do you expect to learn
gosh

Answer 10

do you not think that you should be doing this yourself otherwise you wont learn from it? :)