is it me or is this diffitcut?

Question

List all factor pairs for each given integer.

48

a (2)(24), (3)(16), (4)(12), (6)(8)

b (1)(48), (2)(24), (4)(12), (6)(8)

c (2)(24), (3)(16), (4)(12), (6)(8), (8)(6)

d (1)(48), (2)(24), (3)(16), (4)(12), (6)(8)



List all factor pairs for each given integer.

84

a (1)(84), (2)(42), (4)(21), (6)(14), (7)(12)

b (1)(84), (2)(42), (3)(28), (6)(14), (7)(12)

c (1)(84), (2)(42), (3)(28), (4)(21), (6)(14), (7)(12)

d (1)(84), (2)(42), (3)(28), (4)(21), (7)(12), (8)(9)

Answer 1

A simple way is just to see which answers can be multiplied together to get 48. For the first one, every single one does, so choose the one that has the most right answers, which happens to be the right answer: (d)

The second one is the same, find out which pairs equal 84 and if more than one answer has all it's pair equal to 84, choose the one with the most answers because then it will be the complete set. (c)

To do this without "cheating" and having the answers in front of you, just start dividing from 1 up:

48/1 = 48; (1)(48)
48/2 = 24; (2)(24)
43/3 = 16; (3)(16)
43/4 = 10 3/4; Not an integer
43/5 is not an integer
43/6 = 8; (6)(8)

The next integer you'd get is 43/8=6, which you already have, so stop when you get an answer bigger than what you divided by.

Hope this helps

Answer 2

48 = D
84 = C

Answer 3

for 48 it is d
for 84 it is c

Answer 4

48 - d , 84 - c

Answer 5

48 is d
84 is c

Answer 6

It is you. This is not difficult. The answers are D and C respectively. This is second or third grade math.