2007-11-27 03:47:16 · 4 answers · asked by Tijuana S 1 in Science & Mathematics ➔ Mathematics
36 = 2*3*5. log(36) = log(2*3*2*3) = log 2 + log 3 + log 2 + log 3 = a + a + b + b = 2*a + 2*b.
50 = 2*5*5. log(50) = log(2*5*5) = log 2 + log 5 + log 5 = 2log5 + log2 = 2*c+a.
2007-11-27 03:51:47 · answer #1 · answered by Edgar Greenberg 5 · 1⤊ 1⤋
These are fun! You need to break the 36 and 50 down into 2's, 3's and 5's. Note: You can also use 10 since you know log 10 = 1.
log 36 = log (2^2 * 3^2)
= 2log 2 + 2 log 3
= 2(a) + 2(b) = 2a + 2b
log 50 = log (10*5)
= log 10 + log 5
= 1 + c
that's it!
2007-11-27 11:54:31 · answer #2 · answered by Marley K 7 · 0⤊ 2⤋
log 36 = log 4 x 9 = log 4 + log 9 = 2 log 2 + 2 log 3 = 2a + 2 b
log 50 = log 2 x 5 x 5 = log2 + 2 log 5 = a + 2 c .
2007-11-27 11:53:01 · answer #3 · answered by drmobaid 2 · 1⤊ 2⤋
log 36 = log (2² x 3²)
log 36 = log2² + log 3²
log 36 = 2 log 2 + 2 log 3
log 36 = 2 a + 2 b
log 50 = log (2 x 5²)
log 50 = log 2 + log 5²
log 50 = log 2 + 2 log 5
log 50 = a + 2 c
2007-11-27 11:53:22 · answer #4 · answered by Como 7 · 3⤊ 1⤋