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A 3 digit number for example 1,2,3 can be written in 6 different ways (123,321,231 etc) for higher digit numbers, it becomes a lengthy work, is there any mathematical formula of determining for example a five digit number can be written in how many diff. ways.

2007-11-27 03:46:51 · 3 answers · asked by d_raza1 3 in Science & Mathematics Mathematics

3 answers

Factorial 5: 5! [which means 1x2x3x4x5]

2007-11-27 03:56:07 · answer #1 · answered by answerING 6 · 0 0

Assuming you use each number only once

5 choices for the 1st digit
4 choices for the 2nd digit
3 choices for the 3rd digit
2 choices for the 4th digit
1 choice for the 5th digit

5*4*3*2*1 = 5! (5 factorial) = 120

2007-11-27 12:01:46 · answer #2 · answered by kindricko 7 · 0 0

if there is a N digit no. and every digit is unique then the ans is N!

if there is repeatation ,say there r repeatations in three digit p,q & r times.
then the ans will be

N!/(p!*q!*r!)

2007-11-27 11:59:36 · answer #3 · answered by mazhar 1 · 0 0

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