Set x = 0 and solve it for y.
2007-11-27 00:40:59
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answer #1
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answered by Kimon 7
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The y-intercept is the point on the y-axis where the
line cuts it. At this point, the co-ordinate (x,y) has a
value of 0 for x.
So, if you set x=0 in the given linear equation, you
will find the y term.
For 3x+7y=21, when x=0,
3(0)+7y=21
7y=21, and y=3
The line cuts the y-axis 3 units above the origin,
and its co-ordinate is (0,3)
2007-11-27 08:49:37
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answer #2
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answered by Grampedo 7
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3x+7y=21
Let x = - 1
3(-1)+7y=21
-3 + 7y = 21
7y = 24
y = 24/7
Let x = - 2
3(-2)+7y=21
-6 + 7y = 21
7y = 27
y = 27/7
Let x = 0
3(0)+7y=21
7y = 21
y = 3
Let x = 1
3(1)+7y=21
3 + 7y = 21
7y = 18
y = 18/7
So y-intecept is 3
2007-11-27 10:22:10
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answer #3
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answered by Chan A 3
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At Y-intercept the value of X is equal to 0.
Just plug X=0 into your equation and solve for Y.
2007-11-27 08:41:36
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answer #4
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answered by ArArAt 3
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3x+7y=21
just solve for y
7y = - 3x + 21
y = - 3/7 x + 3
y -intercept = 3
2007-11-27 08:46:43
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answer #5
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answered by CPUcate 6
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y-intercept is the distance where line cuts the y-axis from the origin. Everyone knows at y-axis x=0. put x=0 in given equation and you will get y-intercept equal to 3. Good luck for further problems in maths. I have added you to my contact list for maths i am always there.
2007-11-27 08:50:51
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answer #6
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answered by mat619 2
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y=mx+c
y=(21-3x)7
2007-11-27 08:42:42
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answer #7
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answered by Raga s 3
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y intercept occurs when x = 0
7y = 21
y = 3 is y- intercept.
2007-11-27 10:53:43
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answer #8
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answered by Como 7
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