I scanned in the question from my book, and uploaded it in the form of an image.
http://members.aol.com/theaxegodjehan/img/mathsquestion.PNG
Please help! Thanks.
2007-11-27 00:06:16 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
a). Theorem from geometry: An angle inscribed in a
semicircle is a right angle. Angle QRS = 50 degrees.
b). sin 40 = QS/12. (Basic sine formula).
So QS = 12 sin 40= 7.713(approx).
c). sin 50 = QS/QR = 7.713/QR
QR = 7.713/sin 50 = 10.068(approx)
Hope that helps!
2007-11-27 01:30:48 · answer #1 · answered by steiner1745 7 · 0⤊ 0⤋
Qa> standard theorem
b> use sine rule : sin 90 / 12 = sin 40 / QS
c> similar angle r = 50 deg then use sine rule
2007-11-27 08:15:59 · answer #2 · answered by ASHVIR S 1 · 0⤊ 0⤋
hey dude we actualy have the same geometry leson..wew..!! so pqr is a right angle since segment qs is perpendicular wid segment pr..then here are the formulas..qr=(pr)(sr),qs=(ps)(sr)..cant solve for the values since you only gave the value of 1 segment..at least there shud be 2 values!!
2007-11-27 08:16:43 · answer #3 · answered by arr0n!!! 2 · 0⤊ 0⤋
a) since it is in front of circle diameter, PQR is right angle.
b) QS= PQ * sin 40
c) QR= QS * sin 40
2007-11-27 08:28:41 · answer #4 · answered by King 3 · 0⤊ 0⤋