70.
a. magnesium sulfide
b. nitrogen gas
c. barium hydroxide
d. copper (II) nitride
e. sulfide ion
f. calcium carbonate
g. sodium bromide
h. ferric sulfate
2007-11-26 23:47:49 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
a. MgS
b. N2
c. Ba(OH)2
d. Cu3N2
e. S2-
f. CaCO3
g.NaBr
h. Fe3(SO4)2
2007-11-27 00:20:59 · answer #1 · answered by aayushi_sneha 2 · 0⤊ 1⤋
Phosphate has a total charge of -3, and tungsten(VI) has a total charge of +6. To balance the charges, you need 2 PO4 groups (for a total of 2×-3 = -6) and one W (for a total of +6) giving W(PO4)2. In sulfur dioxide, there is a catch: sulfur is not negative when bound to oxygen. In sulfur dioxide, you can get the formula from the name. Sulfur is S, and dioxide means 2 O atoms, so the formula is SO2. Since O is -2, S must be +4. Cesium cyanate would be CsOCN. Anything ending in -ate means there is oxygen in it, as well as other elements. Cyanide means C≡N, so cyanate would mean adding an oxygen to that. The best way is by making it like this: O-C≡N. Most of those ions have to be learned specifically. If you need more help, send me a message and I'll see what I can do to help out.
2016-05-26 02:34:01 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Ferric is iron +3. Sulfate is SO4 2-.
FeSO4 is ferrous sulfate (iron +2); not the right answer for you.
2007-11-27 00:05:03 · answer #3 · answered by Facts Matter 7 · 0⤊ 1⤋
a. MgS
b. N2
c. Ba(OH)2
d. Cu3N2
e. S-2
f. CaCO3
g. NaBr
h. Fe2(SO4)3
2007-11-27 01:36:00 · answer #4 · answered by ronaq 2 · 0⤊ 1⤋
MgS
N2
Ba(OH)2
Cu3N2
S2-
CaCO3
NaBr
Fe2(SO4)3
2007-11-26 23:54:27 · answer #5 · answered by 8 ball 4 · 0⤊ 0⤋