HCL+CH3COONa?

Question

i have a question about acid buffers: acid buffers r usually mixtures of weak acid and a salt of that acid. here we have solutions from HCL and sodium ethanoate, EXPLAIN how this mixture IS a buffer.
thanks :)

Answer 1

Buffer is salt of strong base and weak acid with weak acid itself.

When acidity is there
weak acid is regenerated with strong base.

When basic media.
Weak acid (along with the salt) is neutrilised by base.
Its called buffer action.

Answer 2

HCl is, as you know, a strong acid, generating hydrogen ions which react with some of the sodium ethanoate to give undissociated ethanoic acid. As long as the amount of HCl was less than the amount of sodium ethanoate, you are left with a mixture of a weak acid and its salt. You could have made the same buffer more directly of course, by using sodium ethanoate and ethanoic acid itself.

Answer 3

THIS MIXTURE IS NOT AN ACID.
there are 2 types of buffer
1. ACID BUFFER- consist of a weak acid and it's salt of a strong base.
example- weak acid-CH3COOH
strong base- NaOH
salt of a strong base- CH3COONa
Therefore the buffer= CH3COOH/CH3COONa

2.ALKALI BUFFER- consist of weak base and it's salt of a strong acid.
example- weak base- NH3
strong acid- HCL
salt of strong acid- NH4CL
therefore the buffer= NH3/NH4CL