My lad is really struggling with is a level
2007-11-26 21:42:26 · 12 answers · asked by K Rigby 1 in Science & Mathematics ➔ Mathematics
"with is a level"? Are you sure you arent the lad in question, also struggling in basic English?
Anyway... as a mathematician, myself, I cannot do jack with what you wrote. There is no question, no objective, no equation, no given independant value... just an arbitrary expression. So... unless you expand and specify... there is no solution.
2007-11-26 21:48:27 · answer #1 · answered by Anonymous · 1⤊ 0⤋
Let's let 6x2-10x-4=0
Then, 12-10x-4=0
8-10x=0
10x=8
x=8/10=4/5=0.8
Good luck!
2007-11-26 22:01:18 · answer #2 · answered by Anonymous · 0⤊ 1⤋
6x2 - 10x - 4
= 12 - 10x - 4
= 12 - 4 - 10x
= 8 - 10x
2007-11-26 23:22:34 · answer #3 · answered by Anonymous · 0⤊ 2⤋
6x² -10x - 4=0
3x² -5x - 2 =0
x = [5 ± √(5² +4(3)(2)) ] / 6
x = [5 ± √(25 + 24) ] / 6
x = [5 ± √49 ] / 6
x = [5 ± 7 ] / 6
x = 12/6 = 2 . . . . . . using the +
x = -2 / 6 = - 1/3 . . . using the -
2007-11-26 21:59:44 · answer #4 · answered by CPUcate 6 · 0⤊ 1⤋
(6x + 2) * (x - 2) is the factorisation of the original expression, which I suspect is what is wanted here.
He needs to look at the original expression and spot that he must find factors of 6 (the first coefficient) and -4 (the last coefficient) which, when cross-multiplied and added, give -10 (the middle coefficient).
The only way to do this is to factorise 6 as 6 * 1, and -4 as -2 * 2
This gives (6x + 2) * (1x - 2)
6x * 1x = 6x^2
6x * (-2) = -12x .......... ] these two terms
2 * 1x = +2x .......... ] add to give -10x
2 * (-2) = -4
which, when multiplied out, gives the original expression, as required.
2007-11-26 21:56:02 · answer #5 · answered by kinning_park 5 · 1⤊ 1⤋
ans: 6x2-12x+2x-4
= 6x(x+2) - 2(x+2)
= (6x-2)(x+2)
either 6x-2 = 0 or x+2=0
hence 6x= 2 or x= -2
hence x= 1/3 or x = -2
2007-11-26 21:50:36 · answer #6 · answered by sant_kulk 2 · 0⤊ 0⤋
easiest way is by factorising
6x2 -10x - 4=0
divide by 2
3x2 - 5x - 2 = 0
(3x+1)(x-2) = 0
therefore either
3x+1 = 0
3x = -1
x = -1/3
or
x-2 = 0
x = 2
2007-11-26 22:20:08 · answer #7 · answered by Damia 3 · 0⤊ 1⤋
It's not even a maths problem - there's no equals sign (or other sign)
If it's for his a level I suggest he figures out how to solve it - he can't ask you or Yahoo Answers in an exam
2007-11-26 23:12:22 · answer #8 · answered by Bob H 3 · 0⤊ 1⤋
6x^2 -- 10x -- 4
= 2[3x^2 -- 5x -- 2]
= 2[3x^2 -- 6x + x -- 2]
= 2[3x(x -- 2) + 1(x -- 2)]
= 2(x -- 2)(3x + 1)
2007-11-26 21:49:18 · answer #9 · answered by sv 7 · 0⤊ 0⤋
But what is the question?
2007-11-26 21:52:26 · answer #10 · answered by Como 7 · 2⤊ 1⤋