2007-11-26 21:29:46 · 4 answers · asked by Yuks 1 in Science & Mathematics ➔ Physics
In series add the Resistances:
Rtotal = R1+R2+R3+.......+Rn
Parallel = add the reciprocals of the resistances
1/Rtotal = 1/R1 +1/R2+1/R3+......+1/Rn
2007-11-26 21:33:42 · answer #1 · answered by iceman 7 · 0⤊ 0⤋
Series Connection:- When two or more resistors are connected in series the total or effective resistance of the combination is the sum total of the individual resistances. If r1, r2, r3 & r4 are the resistors connected in series the resultant resistance R is equal to (r1+r2+r3+r4) ohms.
Parallel Connection :- When two or more resistrors are connected parallel to each other the resultant resistance R will be less than the smallest of the group & can be calculated using the formula 1/R = 1/r1 + 1/r2 + 1/r3 + 1/r4
2007-11-27 00:40:22 · answer #2 · answered by Joymash 6 · 0⤊ 0⤋
Electrical resistance adds up in series:
R(total) = R1 + R2 + R3....
If you put them together in parallel, total resistance drops. This is the equation:
R(total) = 1 / (1/R1 + 1/R2 + 1/R3...)
2007-11-26 21:41:52 · answer #3 · answered by dontpanic66 3 · 0⤊ 0⤋
look . when the added in series total resistance of of the circuit increases . (R=R1+R2+R3+..............)
however when added in parallel the combined Resistance decreases
1/R=1/R1+1/R2+1/R3+........
2007-11-26 23:24:40 · answer #4 · answered by Murtaza 6 · 0⤊ 0⤋