can anyone factor this problem!?

Question

x4-1

Answer 1

(x² + 1)⋅(x² − 1)

(x² + 1)⋅(x + 1)⋅(x − 1)

(x + i)⋅(x − i)⋅(x + 1)⋅(x − 1)

Answer 2

Easy
x^4-1=(x^2+1)(x^2-1)=(x^2+1)(x+1)(x-1)

Answer 3

Easy
x^4-1=(x^2+1)(x^2-1)=(x^2+1)(x+1)(x-1)

Answer 4

I believe the question is to obtain factors for the expression; x^4 - 1
We first note that x^4 - 1 is a difference of two squares and so we can factorize as follows;
x^4 - 1 = (x^2 - 1)(x^2 + 1)
The next step: note again that X^2 - 1 is also difference square. Hence we have, finally;
x^4 - 1 = (x-1)(x+1)(x^2 + 1)

Answer 5

x^4-1
= (x²+1)(x²-1)
= (x²+1)(x-1)(x+1)

Answer 6

I assume you mean x^4 - 1.

x^4 - 1 = (x² + 1)(x² - 1) = (x² + 1)(x + 1)(x - 1)

Answer 7

did you mean x^4-1? if so,
it is (x^2-1) times (x^2+1)
(x^2-1)
(x^2+1)

multiply 1st x^2 and x^2 = x^4

then multiply x^2 with -1 = negative x^2
multiply 1 with x^2 = positive x^2
(*this makes the two answers equal to zero x^2 -x^2 =0)

then finally multiply 1 with -1= -1

thus the final answer is
x^4-1

Answer 8

You cannot factor a problem
You factor a polynomial.