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I am having trouble evaluating this integral. Integrate 0 to T (x^4 - 8x + 7) dx

2007-11-26 18:43:13 · 2 answers · asked by xìn xīn 1 in Science & Mathematics Mathematics

2 answers

That would be

x^5 / 5 - 8x^2 / 2 + 7x ] from 0 to T

=(1/5)T^5 - 4T^2 +7T - ((1/5)0^5 - 0T^2 +0T)

=(1/5)T^5 - 4T^2 +7T

Good luck!

2007-11-26 18:48:39 · answer #1 · answered by Anonymous · 3 1

I = ∫ x^4 - 8x + 7 dx
I = x^5/5 - 4x² + 7x between 0 and T
I = T^5/5 - 4T² + 7T

2007-11-27 11:20:58 · answer #2 · answered by Como 7 · 1 1

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