I got this puzzle for my Psych class to do where you have to touch everyborder without it going over it twice in a continuous line.
Heres a picture of what it the puzzle is and the other picture is what i got soo far, i still didn't get to touch the top right line. Its driving crazy!
http://i17.photobucket.com/albums/b60/xashleyleyx/DSC01895.jpg
http://i17.photobucket.com/albums/b60/xashleyleyx/DSC01896.jpg
Basically the continuous line can cross over itself just as long as its not going over the border more than once.
also if anyone knows the name of this puzzle i would greatly appreciate it.
2007-11-26 18:06:35 · 5 answers · asked by xashleyleyx 4 in Science & Mathematics ➔ Other - Science
no that one is an exeption. (quapie)
2007-11-26 18:31:57 · update #1
this problem has no solution.
because it has 3 locations (3 rectangles) which have an odd number of lines leaving each of them.. And also the outside has an odd number of lines coming to it (or leaving it)
a continuos line can have only only 2 loose ends.
a continuous path (Euler's path) may have a maximum of two spaces with odd lines leaving it (or arriving at it)
See Euler's theorem on graphs
It is generalized from Konigsberg's 7 bridges problem -
it has no solution either as proven by Euler
2007-11-26 21:30:45 · answer #1 · answered by realme 5 · 1⤊ 0⤋
7 Bridges Puzzle
2016-12-12 06:12:15 · answer #2 · answered by ? 4 · 0⤊ 0⤋
This is known as the Konigsberg problem, because old Konisberg in Germany had three islands connected by 7 bridges, and the problem was to find a route over all seven bridges, without going over one twice. Graphically, it is exactly the same as the problem in your puzzle. As others have said, the problem was solved by Euler in the eighteenth century.
If you look up Kongsberg (or Euler) in Wikipedia, you should find a simple explanation
Edit: Sorry, kongsberg is in Russia, not Germany.
Here's a reference to the "7 Bridges of Konigsberg" problem:
http://en.wikipedia.org/wiki/Seven_Bridges_of_K%C3%B6nigsberg
2007-11-27 00:21:54 · answer #3 · answered by AndrewG 7 · 1⤊ 0⤋
wouldn't the bottom border of the top center box be considered 1 border. If so you have it crossed twice.
If not let me know. I am working on it but am not having any luck.
no answer per- link by Dennis
2007-11-26 18:30:14 · answer #4 · answered by Sebastian 2 · 0⤊ 1⤋
There is no solution to this. Check the page below for why.
Look under 032 Walls & Lines.
2007-11-26 18:28:45 · answer #5 · answered by dennis f 3 · 0⤊ 1⤋